# Evaluating the quotient without the calculator

Without using the calculator find the value of $$\frac{3^{750}}{5^{510}}$$ I tried to consider $$\frac{3^{750}}{5^{510}}=x$$ Then i took log to both sides to be $$750\log{3}-510\log{5}=\log{x}$$ But i could not do any thing more ?

• I find it very doubtful that you're not allowed to involve the use of a calculator at any point.. Are you sure you're not being asked to evaluate it in a way that is feasible with a calculator? The average calculator can't handle $3^{750}/5^{510}$, but it can certainly handle $10^{(750\log3 - 510\log5)}$ – AlkaKadri Jan 15 '18 at 22:17

This is a good start. If you are permitted log tables, you can look up $\log 3$ and $\log 5$ and do the calculation you indicate, then use the tables to get $x$. Otherwise, I don't see any way. It turns out that $\frac {3^{747}}{5^{510}}$ is just slightly less than $1$ and the final answer is about $23.24$
Supposing you're also not allowed logarithm tables, let's see if we can get some crude guesses about logarithms: $$\begin{array}{ccc} n & 3^n & 5^n \\ \hline 1 & 3 & 5 \\ 2 & 9 & 25 \\ 3 & 27 & 125 \\ \vdots & \vdots & \vdots \end{array}$$ So we have $3^3 \approx 5^2,$ so $5^{2/3} \approx 3,$ so $\log_5 3 \approx 2/3.$
But $3^3>5^2,$ so $5^{2/3} < 3,$ so $\log_5 3 >2/3.$
$$(750\log_5 3) - 510 \approx \frac 2 3 \cdot750 - 510 = 500 - 510 \approx \cdots$$
But $2/3$ was a bit too small, so maybe around $510 - 510\text{ ?}$ However, that cannot be exact, because $3$ and $5$ are prime numbers, so the numerator and denominator cannot have any factors that cancel each other. If the logarithm were $0$ then the quotient would be $1.$ So it's probably not far from $1.$
With a calculator I'm getting $750\log_5 3 \approx 511.95.$