Some maths to usher in the New Year!
Find distinct integers $a,b,c,d,e,f,g,h$ such that $$\color{purple}{\binom ab+\binom bc}+\color{blue}{\binom cd}+\color{green}{\binom de+\binom ef}+\color{orange}{\binom fg+\binom gh}=\color{red}{2018}$$ and where $a>b>c>d>e>f>g>h\ge 0$, and one of the binomial coefficients is $$\color{red}{\binom {20}{18}}$$
Alternatively, in summation form:
Find distinct integers $x_1, x_2, \cdots, x_8$ such that $$\color{orange}{\sum_{n=1}^7}\color{orange}{\binom {x_n}{x_{n+1}}}=\color{red}{2018}$$ and where $x_n>x_{n+1}\ge0$ and, for one particular value of $n$, $$\color{green}{\binom {x_n}{x_{n+1}}}=\color{red}{\binom {20}{18}}$$ Happy New Year!