# How to convert (standard) primal form to (standard) dual form [closed]

I'm working on a HW assignment as follows:

Given the primal canonical problem: $$\min \langle c,x \rangle \quad \text{s.t}: Ax \geq b, x \geq 0$$ and the dual canonical problem: $$\max \langle b,y \rangle \quad \text{s.t}: A^Ty \leq c, y \geq 0$$

Show that converting PC (primal canonical) to DC (dual canonical) is similar when done directly or when done via canonical to standard conversion (i.e. primal canonical -> dual canonical == primal canonical -> primal standard -> dual standard -> dual canonical).

I converted the CP to SP (standard primal) by adding slack variables $s_1,\dots,s_n\geq 0$ and adding them to each inequality.

My problem is showing the similarity between the SP and SD (standard dual).

What I've done so far is this: SD (standard dual) wants to maximize $b^Ty$ so:

1. $b = Ax$
2. $b^T y = (Ax)^Ty = (x^TA^T)y = x^T(A^Ty) \leq x^Tc$

Now, I don't know how to proceed. How can I show that minimizing $c^Tx$ is maximizing $b^Ty$? Am I on the correct path?

PS: I am pretty sure dual and primal problems can be shown where the primal is max and the dual is min, but I think it doesn't matter at all, right?

## closed as off-topic by Jack D'AurizioMar 13 '18 at 17:11

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