# How to prove $\prod_{k=1}^{\infty}{\frac{p_k^2+1}{p_k^2-1}}=\frac{5}{2}$?

I came across the following formula due to Ramanujan:

$$\prod_{k=1}^{\infty}{\frac{p_k^2+1}{p_k^2-1}}=\frac{5}{2}.$$

Can someone show me what the proof of this looks like, or point me to a reference (in English)?

By Euler's product, for any $s>1$ we have $$\zeta(s)=\sum_{n\geq 1}\frac{1}{n^s} = \prod_{p}\left(1-\frac{1}{p^s}\right)^{-1} \tag{A}$$ hence $$\prod_{p}\frac{p^2+1}{p^2-1} = \prod_p\frac{1-\frac{1}{p^4}}{\left(1-\frac{1}{p^2}\right)^2} = \frac{\zeta(2)^2}{\zeta(4)} = \frac{90}{36} = \frac{5}{2}.\tag{B}$$ Similarly, $\prod_{p}\frac{p^4+1}{p^4-1}=\frac{7}{6}$.