open sets and Borel sets on the extended real line I know the definition of an open set and a Borel set on the real line $\mathbb R$:  
(1) $A \subset \mathbb R$ is open if every $x \in A$ is an interior point, i.e. there exists some $\delta>0$ s.t. $y\in A$ whenever $|y-x|<\delta$.
(2) The collection $\mathcal B$ of Borel sets is generated by the class of open sets in $\mathbb R$.
I'm not sure how these two definitions should be modified when we work with the extended real line, i.e. $\overline {\mathbb R}=\mathbb R \cup \{-\infty, \infty\}$?  
In particular, consider, for instance, the openness of $A\triangleq(1, \infty]$.  Obviously every $x\in (1, \infty)$ is an interior point of $A$, according to the definition above.  But what about $x=\infty$?  Clearly no real number $y$ would be within any finite distance from $\infty$, and $\infty-\infty$ is undefined.  So it's not clear to me if and how $\infty$ should be considered an interior point of $A$?
Is the collection $\overline {\mathcal B}$ of Borel sets in $\overline{\mathbb R}$ still defined as the $\sigma$-field generated by open sets in $\overline{\mathbb R}$?
I know only the basics of analysis and measure theory.  I'd appreciate it if someone can help me out here.  Thanks a lot!
 A: The extended real line is homeomorphic to the interval $C=[0,1]$ with the usual topology inherited from the real line. 
So, you know all the open sets in the extended real line by knowing the open sets on $C$. 
As to the neighborhoods of $\infty$, this quote from the Wiki page explains (note the last line).

In this topology, a set U is a neighborhood of  $\infty$  if and only if it contains a set
  $\{x : x > a\}$ for some real number  a, and analogously for the
  neighborhoods of $-\infty$. The extended real line is a compact
  Hausdorff space homeomorphic to the unit interval [0,1]. 
  Thus the topology is metrizable, corresponding (for a given
  homeomorphism) to the ordinary metric on this interval. **There is no
  metric that is an extension of the ordinary metric on $\mathbb{R}**$.

And yes, the Borel sets are still the $\sigma$-field generated by these open sets. 
Edit: I would like to add from DanielWainFleet’s excellent characterization below, pointing out that $B$ is a Borel set in the extended reals if $B\setminus\{\infty, -\infty\}$ is a Borel set in the reals. 
