# How to solve Rudin Chapter 2 problem 11? [duplicate]

I have finished the entire problem except the 5th part. Roughly speaking the questions asks to show that over $\mathbb{R}$ prove/disprove that the distance function

$$d_5(x,y) = \frac{|x-y|}{1 + |x-y|}$$

Is a metric. I have proven symmetry and I have proven that if $d_5(x,y) = 0$ that $x = y$ so all that remains to be shown is the triangle inequality namely :

$$\frac{|x-y|}{1 + |x-y|}+ \frac{|y-z|}{1 + |y-z|} \ge \frac{|x-z|}{1 + |x-z|}$$

This of course can be cast more simply in terms of $u,v$ in $\mathbb{R}$ as

$$\frac{|u|}{1 + |u|}+ \frac{|v|}{1 + |v|} \ge \frac{|u+v|}{1 + |u+v|}$$

This reminds me an awful lot of contest style inequalities but i can't for the love of god place which one this is (not that it should matter, I should ideally be able to just generate a proof with ease).

My one angle of attack was to do case work on fixing $u,v$ to be both positive or both negative, or a mix of positive and negative. But is there a easier way to proceed than that?