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given the rectangle described by:

$0\leq x \leq 6$, $0 \leq y \leq 2$

And a fluid following the vector field:

$F = \langle x^3+2, y \cos(6x) \rangle$

We get the 2D curl:

$curl(F) = -6y\sin(6x)-0=-6y\sin(6x)$

By green's theorem, the flux through the boundary is thus:

$\int^6_0\int^2_0 -6y\sin(6x) dydx = -4\sin^2(18)$ (by wolfram, manually I got $-2\cos(36)$)

Neither of these answers is correct and I am not sure where the problem is.

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  • $\begingroup$ $\int \cos(6x) dx = \frac{1}{6} \sin(6x) + C$ $\endgroup$ – infinitylord Dec 11 '17 at 3:44
  • $\begingroup$ I believe the flux is related to the divergence, not the curl $\endgroup$ – Alex Pavellas Dec 11 '17 at 4:53
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\begin{align} \int^6_0\int^2_0 -6y\sin(6x) dydx &= \int^6_0\sin(6x)dx\int^2_0 -6y dy \\ &= \dfrac{-\cos6x}{6}\Big|^6_0\dfrac{-6y^2}{2}\Big|^2_0 \\ &= \dfrac{1-\cos36}{6}\dfrac{-24}{2} \\ &= \color{blue}{-4\sin^218} \end{align}

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  • $\begingroup$ Which is not the correct answer as I said $\endgroup$ – Makogan Dec 11 '17 at 4:09
  • $\begingroup$ The integral gives this answer, so your fault comes from other part! $\endgroup$ – Nosrati Dec 11 '17 at 4:11
  • $\begingroup$ Hence why I described the entire problem and then gave my solution, so that people could identify what error I made $\endgroup$ – Makogan Dec 11 '17 at 4:18
  • $\begingroup$ I thought you want to verify the integral answer. Anyway I will check your solution. How did you find it with wolfram? $\endgroup$ – Nosrati Dec 11 '17 at 4:21
  • $\begingroup$ To simplify my query, I need the answer (and know how to get the answer) to the problem: Find the flux of $F=\langle x^3+2, ycos(6x) \rangle$ through the boundary of the rectangle $0 \leq x \leq 6$; $0 \leq 2 \leq 2$ $\endgroup$ – Makogan Dec 11 '17 at 4:26
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I attempted to solve this.

$\frac{\partial F1}{\partial y}=0\ \ \ \frac{\partial F2}{\partial x}=-6ysin(6x)$

$\int^6_0 \int^0_2 -6ysin(6x) \ dydx $

$\int^6_0 -6ysin(6x) \ dx ]^2_0 = \int^6_0 -12sin(6x) \ dx$

$\frac{12}{6}cos(6x)]^6_0 = 2[cos(36)-1]$

Which is basically the same answer. What is the answer you are trying to attain?

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