how to find probalility that a student misses at least one test if he/she is absent twice? 
The probability that a teacher will give an unannounced test during any class is $\dfrac15$. If a student is absent twice then probability that he/she misses at least one test is
$\\ \hspace{5cm}$ a) $\dfrac23\ \quad $ b) $\dfrac45\ \quad$c) $\dfrac7{25}\ \quad $d) $\dfrac9{25}\ $

My attempt:
Probability of attending first test & missing $2$nd test $=\dfrac45\times\dfrac15=\dfrac4{25}$
Probability of missing first test & attending $2$nd test $=\dfrac15\times\dfrac45=\dfrac4{25}$
Probability of missing both the tests $=\dfrac15\times\dfrac15=\dfrac1{25}$
Total probability of missing at least one test $=\dfrac4{25}+\dfrac4{25}+\dfrac1{25}=\dfrac9{25}$
Can somebody please help me if I am wrong? Thanks.
 A: Questions with "at least" are often great candidates for using the complement. That is: $$P_{\text{ Event A occurs }} = 1 - P_{\text{ Event A does not occur }}$$
So, $P_{\text{ miss at least 1 test }} = 1 - P_{\text{ miss no tests }}$ giving us: 
$$\begin{align*} P_{\text{ miss no tests }} & = P_{\text{ no test on day 1 AND no test on day 2 }}\\
& = P_{\text{ no test on day 1 }} \times P_{\text{ no test on day 2 }}\\
& = \frac{4}{5} \times \frac{4}{5}\\
& = \frac{16}{25}\end{align*}$$
So, $$P_{\text{ miss at least 1 test }} = 1 - P_{\text{ miss no tests }}
= 1 - \frac{16}{25} 
= \frac{9}{25}$$
A: Another way to see this is that the probability of the student missing at least one test is the probability of missing test 1 + the probability of missing test 2 - the probability of them missing both tests. 
The student has $\frac15 $chance of missing the first test, and $\frac15 $ chance of missing the second test. If you add them up you're left with $\frac 25$. HOWEVER there is a case that is being counted twice: It could happen that the student misses test 1 AND test 2. That case is being counted both when the student misses test 1 and when the student misses test 2. So now we have to substract this case once
The chance of a test happening on two consecutive days is $(\frac 15)^2 = \frac {1} {25}$.
So the answer is $\frac 25 - \frac {1} {25} = \frac {9} {25}$
The general case for this is $$P(A \cup B) = P(A) + P(B) - P(A \cap B)$$ 
