Given a local field complete with respect to a discrete valuation, does that imply it is non-Archimedean?

At the beginning of the section of a book I am reading it says $K$ is a local field complete with respect to a discrete valuation. Local fields can be archimedean or non-archimedean. Does the condition that it has a discrete valuation imply we are only dealing with non-archimedean local fields? Thank you very much.

• Could you add how that book defines "discrete valuation" and "local field"? I have an idea what is meant, but sometimes there are subtle differences. In particular, many sources I know define a local field as non-archimedean to begin with, but in your situation that seems not to be the case. – Torsten Schoeneberg Dec 12 '17 at 18:55
• What I mean is: Whatever the definition of "archimedean local field" is here, I am quite sure it must contain $\mathbb{Q}$ as a subfield, and the valuation restricted to that must be equivalent to the usual absolute value. And I would be surprised if any definition of "discrete valuation" includes this. – Torsten Schoeneberg Dec 14 '17 at 18:28
• @TorstenSchoeneberg I was searching around the book, but it actually doesn't define what a local field or discrete valuations are... It's actually Silverman-The arithmetic of elliptic curves. I looked up Wikipedia for definition of local field and then it says there are archimedean and non-archimedean ones and I got confused... – Johnny T. Dec 14 '17 at 20:05
• Ah. Well, Wikipedia goes with the definition "locally compact w.r.t. a non-trivial valuation". Then the Archimedean ones are precisely $\mathbb{R}$ and $\mathbb{C}$. But the valuation on those is not discrete. So yes, that section of the book will be dealing with nonarchimedean local fields. – Torsten Schoeneberg Dec 14 '17 at 21:33
• @TorstenSchoeneberg Do you have an exact definition in mind of what the local field is for this book by any chance? I'd be happy to take that the as the answer for this question... – Johnny T. Dec 15 '17 at 10:36

An absolute value on a field $K$ is a map $|\cdot|: K \rightarrow \mathbb{R}_{\ge 0}$ such that $$|x| = 0 \Leftrightarrow x = 0,$$ $$|xy| = |x||y|,$$ $$|x+y| \le |x|+|y|.$$ An absolute value defines a metric on $K$ by $d(x,y) := |x-y|$, which in turn defines a topology on $K$.

The value is called nonarchimedean if $$|x+y| \le \max(|x|, |y|)$$ which is equivalent to its induced metric being an ultrametric. On the equivalence of alternative conditions/definitions for this, see here.

The trivial absolute value is $|x| = 1$ for all $x \in K^*$. It is nonarchimedean, but boring, and we exclude it.

A value is called discrete if its value group $|K^*|$ is discrete in $\mathbb{R}$. (Here is a possible source of confusion: The trivial value induces what is often called the discrete metric and discrete topology. Now the trivial value is also a discrete value, but what we are interested in from now on, on the other hand, are non-trivial discrete values, which do not induce the discrete topology.)

After all this preamble, a local field is a field with a non-trivial absolute value such that the induced topology is locally compact.

One can show that a local field whose value is archimedean is either $\mathbb{R}$ or $\mathbb{C}$. The value in theses cases, however, is non-discrete (the value group is all of $\mathbb{R}_{\ge 0}$.)

If, on the other hand, the value is discrete, then one can show that the field is either

1. a finite extension of the $p$-adic numbers $\mathbb{Q}_p$ for some prime $p$, or
2. a field of formal Laurent series $\mathbb{F}_q((T))$ over a finite field $\mathbb{F}_q$.

Note that in both cases the residue field is finite. In the first case, $K$ has characteristic $0$, (sometimes called "the mixed characteristic case"), whereas in the second case, $K$ and its residue field share the same positive characteristic. Further, the absolute value is (equivalent to) the $p$-adic value in the first case, and in both cases the value group is of the form $r^\mathbb{Z}$ where $r$ is some positive real number $\neq 1$. The most common choices for $r$ are the cardinality of the residue field $q$, or its characteristic $p$. As one learns early, this is of no real importance, and for these discrete values one most often switches from the multiplicative absolute value $|\cdot|$ to the additive valuation $val := -\log_r | \cdot |$, whose value group is just the additive group $\mathbb{Z}$.