There is a chessboard of size $8\times 8$. I am given dominoes of size $1\times 2$ and of a single color (assume, it has a color). It is possible to place a domino on the board so that it covers exactly two squares. I can't place two dominoes on the same square and I can't place a domino so that it is partially off the board.
a) How many ways are there to place a single domino on the board( I place it only horizontally or vertically) My Answer is : 112
b)How many ways are there to place two different dominoes on the board(red domino and blue)? My Answer is : $1024$ (But, I'm not sure at all)
c)How many ways are there to place two blue dominoes on the board? I don't know how to approach to this question. I have started to learn Combinatorics this year, and kind of stuck. Thank you, in advance.