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If we have $$\sqrt[2]{x}^{2} = \sqrt[2]{x^2} = |x|$$ so : $$\sqrt[2]{-1}^{2} = \sqrt[2]{-1^2} = |-1| = 1$$ so why we say $i^2 = -1$?

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    $\begingroup$ Well I say that $i^2$ equals $-1$ because it equals $-1$. I don't say $i^2$ equal $1$ because it doesn't equal $1$. $\endgroup$ Nov 29, 2017 at 19:28
  • $\begingroup$ This question is massively a duplicate, but I can't find the One True Answer - math.stackexchange.com/questions/1096917/… is an example. $\endgroup$ Nov 29, 2017 at 19:30
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    $\begingroup$ Logical reason? It's the definition of $i$... $\endgroup$
    – ziggurism
    Nov 29, 2017 at 19:31

1 Answer 1

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$$\sqrt{x^2}\neq (\sqrt{x})^2$$

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