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I am trying to solve $e^x \sin(x) + e^y \cos(y) \cdot y' =0$.

Trying to solve it via separation of variables or treating it as an exact differential equation, I end up solving

$\frac{1}{2} (e^x (\cos x-\sin x) + e^y (\sin y+\cos y) + C = 0$ for $y(x)$ ($C$ being a constant).

I tried different things in order to come closer to a solution (or showing that there is none), but nothing worked (mathematica for example says it cannot be solved). Do you have any ideas?

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    $\begingroup$ An equation defining the function implicitly can perfectly be the way to present the solution of a differential equation. $\endgroup$ – arts Nov 24 '17 at 18:16
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    $\begingroup$ no Chance to find an explicit solution $\endgroup$ – Dr. Sonnhard Graubner Nov 24 '17 at 18:19
  • $\begingroup$ @Dr.SonnhardGraubner Can I somehow proof this? $\endgroup$ – Vazrael Nov 24 '17 at 18:20
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the solution is given by $$e^y(\cos(y)+\sin(y))=e^x(\cos(x)-\sin(x))+C$$

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  • $\begingroup$ then try it, it is wasting time $\endgroup$ – Dr. Sonnhard Graubner Nov 24 '17 at 18:30

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