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I'm already long time from school. I want to solve y from this equation:

$x = 10^\frac{(y - 109)}{32}$

How can I do that?

In real life y is the rain intensity, and x is number of millimeters rain per hour.

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  • $\begingroup$ Take log base 10 from both sides, and proceed. $\endgroup$ – user202729 Nov 24 '17 at 12:10
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$$\frac{y-109}{32}=\log_{10}x$$ or $$y=32\log_{10}x+109.$$

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Take the (decimal) logarithms of both sides: $$\frac{y-100}{32}=\log x$$ I think you can easily end the computation.

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