Find the taylor series of the function $$f(x) = 8(x-12)ln(x-12)$$ about $x = 13$. Give the taylor polynomial of degree 3 as your answer. Then find the interval of convergence for the series.
I found the taylor polynomial of degree 3 to be the following: $$8(x-13) + \frac82(x-13)^2 -\frac43(x-13)^3$$ not sure if this is right though. I haven't been able to write the series in sigma notation, and therefore haven't been able to find the interval of convergence. The problem doesen't require you to write out the series in sigma form though, so if there's any other way to find the intervall of convergence, that would work as well.