# Solve the following linear differential equation with constant coefficient.

In the above image, (Example 13) I have formed the Auxiliary equation i.e. And tried to solve the equation by "real root theorem". But could not find the solution.

• So the equation is $$y^{(4)}-4y'''+8y''-8y'+4y=0$$?? – Dave Nov 16 '17 at 15:52
• Yes. It is the Question . – Akshie Dhiman Nov 16 '17 at 15:54

HINT $$\begin{split} p(m) &= m^4 - 4m^3 + 8m^2 - 8m + 4 \\ &= \left(m^2 - 2m + 2\right)^2 \end{split}$$