Suppose that a deck of 52 cards containing four aces is shuffled thoroughly and the cards are then distributed among four players so that each player receives 13 cards. Determine the probability that each player will receive one ace.
The answer to this is given as$$\frac{13^4}{\binom {52}4}$$
My doubt is the following:
- The book justifies ${\binom {52}{4}}$ as number of possible different combinations of the four positions in the deck occupied by 4 aces. That sounds like a case of arrangements to me, so shouldn't we think about permutations and not combinations if we are concerned about how the aces are to be arranged in the deck ?.
- Shouldn't the denominator be ${\binom {52}{13}}$ since you are choosing 13 cards for 4 people.