I'm here to ask for a simple question about unit quaternions. I have a quaternion, say $q_1$. Now, I would like to choose between $q_2$ and $-q_2$ (that represent the same rotation), by choosing the one that has the "smallest distance" to $q_1$. I can give an example of my question, then it is clearer to everyone. Actually, $q_1$ and $q_2$ is the same quaternion in two time instants. Since in my computations I have functions of the single elements of $q_2$, it is important the sign of those elements. Then, I would like the quaternion that is "more similar to" $q_2$. Roughly speaking, if my quaternion is [1 0 0 0] and then I have [0.99 0 0 0.1411] and [-0.99 0 0 -0.1411], I would like to choose the first one.

I have search in the web without a clear answer to this question, even because there can be cases in which the difference is not so evident as in the example that I provided above. Many thanks in advance for your reply.

Regards, Neostek

  • $\begingroup$ Why don't you just minimize the angles between the axis of your reference quaternion and the axes of the two candidates? $\endgroup$ – rschwieb Nov 14 '17 at 16:13
  • $\begingroup$ Leave me a comment if you have more questions. $\endgroup$ – Zhuoran He Nov 16 '17 at 16:37

The product between two quaternions $q_1=(a_1,\vec{v}_1)$ and $q_2=(a_2,\vec{v}_2)$ is given by


Therefore, the inner product between $q_1$ and $q_2$ as $\mbox{4D}$ vectors in $\mathbb{R}^4$ is given by


where $\,|q_1|=|q_2|=1\,$ for unit quaternions. Therefore, the inner product $\,\mathrm{Re}(q_1q_2^*)=\cos\theta\,$ gives the cosine of the angle $\,\theta\,$ between $\,q_1\,$ and $\,q_2\,$ as vectors in $\,\mathbb{R}^4$. You can then make the choice based on which angle $\,\theta\,$ is smaller. One can prove that the law of cosine


applies to quaternions as well. Therefore the angle reflects the distance for unit quaternions. Note that $\,(q_1q_2^*)^*=q_2q_1^*\,$ (not $\,q_1^*q_2\,$ in general because quaternion product does not commute).


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