# Convolution and laplace transform of an ODE

I was wondering if it was possible to use convolution to solve $$y'' +3ty'-6y=\sin(t)$$ How would you use convolution on the $3y't$ part, or is that even allowed?

• I don't see the Convolution used. Nov 13 '17 at 5:39

$$\mathscr{L}_t\left[\text{n}\cdot t\cdot\text{y}\space'\left(t\right)\right]_{\left(\text{s}\right)}=\text{n}\cdot\mathscr{L}_t\left[t\cdot\text{y}\space'\left(t\right)\right]_{\left(\text{s}\right)}\tag1$$
$$\text{n}\cdot\mathscr{L}_t\left[t\cdot\text{y}\space'\left(t\right)\right]_{\left(\text{s}\right)}=-\text{n}\cdot\frac{\text{d}}{\text{d}\text{s}}\left\{\mathscr{L}_t\left[\text{y}\space'\left(t\right)\right]_{\left(\text{s}\right)}\right\}\tag2$$
$$-\text{n}\cdot\frac{\text{d}}{\text{d}\text{s}}\left\{\mathscr{L}_t\left[\text{y}\space'\left(t\right)\right]_{\left(\text{s}\right)}\right\}=-\text{n}\cdot\frac{\text{d}}{\text{d}\text{s}}\left(\text{s}\cdot\text{Y}\left(\text{s}\right)-\text{y}\left(0\right)\right)=-\text{n}\cdot\left(\text{s}\cdot\text{Y}\space '\left(\text{s}\right)+\text{Y}\left(\text{s}\right)\right)\tag3$$