This is a three-unknown equation. I have to get three lines there.
Let a = a three digit number, e.g 246, 371 //just for further thinking
Let x = a's ones place
Let y = a's tenths place
Let z = a's hundreds place
I've got these two lines already, just cannot get the third.
x + y + z = 11
3x = y
Here i have to put this into maths: If we flip the number like: 246 -> 642 or 371 -> 173 the new number is bigger than the old number by 297.
EDIT Added more information (because I messed something up there):
All the three digits of the number added must equal 11;
The ones place is 3 times bigger than the tens place;
Flipped number is 297 greater than the original number;
Can you help me figure this out?
Would really appreciate you help!!
EDIT2:The final equation system:
$$x+y+z=11$$ $$100x+10y+z−(100z+10y+x)=99(x−z)=297⟹x−z=3$$ $$x=3y$$ Thanks to Math Lover!