This is a calculus problem. I don't know Russian.

Показать, что существуют последовательности, расходящиеся в $+\infty$ (сходящиеся к нулю) и несравнимые с точки зрения скорости стремления к $+\infty$ (сходимости к нулю).

  • $\begingroup$ Show that there are sequences, divergent in + ∞ (converging to zero) and the incomparable in terms of rate of convergence to + ∞ (convergence to zero.) $\endgroup$ Dec 4, 2012 at 11:30
  • $\begingroup$ That's what Google translate gives me. You'd get a better answer if we knew the context. $\endgroup$ Dec 4, 2012 at 11:31

1 Answer 1


Show that there exist sequences which diverge (namely limit of sequence equals $+\infty$) (or converge to 0) and these sequences aren't compareble with respect to rate of convergence (or rate it goes to infinity with(i.e. diverge)). Is my wording clear?I'm sorry for my English.

  • $\begingroup$ Well, that's exactly what I thought it said, yet I couldn't make any sense of it...sorry. $\endgroup$
    – DonAntonio
    Dec 4, 2012 at 11:29
  • $\begingroup$ @unknown That's O.K. Thanks. $\endgroup$ Dec 4, 2012 at 11:44
  • $\begingroup$ For example 1/n and 1/(n^2). limit equals 0 for each sequence. but their ratio equals n. therefore the limit of their ratio equals infinity, i.e. these sequences have different rates of convergence. If the ratio equals 1 then sequences're called equivalent $\endgroup$
    – unknown
    Dec 4, 2012 at 11:52

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