How can I evaluate
$$ \lim_{n \rightarrow \infty} \frac{n\sin n}{2n^2- 1}? $$
Unsuccessful attempt:
In the expression $\frac{n\sin n}{2n^2 - 1}$, I divided the numerator and denominator by $n^2$, but I got stuck with $\frac{\sin n}{n}$ and I do not know how to go on.
Any help will be appreciated.