Given a real, symmetric and positive-definite matrix G. G' = transposed matrix of G

Please, could you tell me which class of matrices that satisfy: Frobenius norm of G = [trace(GG')]^1/2 = trace[(GG')^1/2]


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    $\begingroup$ If $G$ is symmetric, then $G = G'$... $\endgroup$ – amsmath Oct 30 '17 at 22:45
  • $\begingroup$ You should try to savage the answer to your last question. If you need a hint: rank $1$ matrices. $\endgroup$ – user251257 Oct 30 '17 at 22:57

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