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I have been attempting quite a few of these "find the matrix from the linear transformation" problems and I have been stuck on this problem for some time. For the standard bases what I have is

\begin{bmatrix} p(1) & 0 & 0 \\ 0 & p\prime(1) & 0 \\ \\ 0 & 0 & p\prime\prime(-1) \end{bmatrix}

and here's what I have for the other basis

\begin{bmatrix} p(1) & p(1) & p(1) \\ 0 & p\prime(1) & p\prime(1) \\ \\ 0 & 0 & p\prime\prime(-1) \end{bmatrix}

Thanks in advance!

Let $T:P_3(\mathbb{R})\rightarrow\mathbb{R^3}$ be the linear transformation given by $$T(p)=(p(1), p\prime(1), p\prime\prime(-1))$$.

Find the matrix of $T$ relative to the standard basis of $P_3(\mathbb{R})$ and the basis $$v_1=(1,0,0), v_2=(1,1,0), v_3=(1,1,1)$$ of $\mathbb{R^3}$

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  • $\begingroup$ Why do you tell us what the standard basis of $P_3(R)$ actually is, and for each vector $p$ in that basis, tell us what you computed as $T(p)$?That wy we'll know a bit more of what you actually know how to do. (You can edit your question by clicking on "edit" just below the question, to show your partial work.) $\endgroup$
    – John Hughes
    Oct 27, 2017 at 23:42
  • $\begingroup$ What are you getting stuck on? $\endgroup$
    – copper.hat
    Oct 27, 2017 at 23:50
  • $\begingroup$ What is $P_3(\mathbb{R})$? Is it the vector space (algebra actually) of the polynomials of degree less than $3$, at most $3$, or something else? Telling us the "standard basis" would have clarified the question $\endgroup$
    – Tancredi
    Oct 27, 2017 at 23:54
  • $\begingroup$ Agree with john hughes on this that it would be more helpful if you show what you've done. Best $\endgroup$
    – vkan
    Oct 28, 2017 at 0:16
  • $\begingroup$ I have edited the post. $\endgroup$
    – john fowles
    Oct 28, 2017 at 0:42

1 Answer 1

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Hint: would suggest by writing $p=ax^2+bx+c$ and seeing what happens to it by applying the transformation T.

(If the non-standard basis of $\mathbb{R}^3$ is confusing then perhaps do the problem with respect to the standard basis first).

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