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Suppose I have matrices $A,B$ both of dimension, $2m$ by $2$. Then $$AB^TBA^T$$ is of dimension $2m$ by $2m$, $A^T$ denotes the transpose of $A$. I know that rank would mean the number of linearly independent vectors but what makes me confused is when my teacher said that if the rank of $A$ is 1 then the product of the matrices above is equal to the zero matrix.

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Let $m=1$ and let $A = \begin{bmatrix}1&0\\1&0\end{bmatrix}$ and $B = \begin{bmatrix}1&0\\0&1\end{bmatrix}$. Then $A$ has rank $1$, but $$AB^\top B A^\top = AA^\top = \begin{bmatrix}1&1\\1&1\end{bmatrix}$$ is not the zero matrix.

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  • $\begingroup$ Oh yea. I will inform my teacher. Thanks $\endgroup$ – Karamatimatika Oct 23 '17 at 3:19
  • $\begingroup$ But am I correct to say that if n<=m is the rank of a matrix then if I express in in RREF, I will have n nonzero rows? $\endgroup$ – Karamatimatika Oct 23 '17 at 3:20

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