# How to rewrite this term?

So I have a term like this:

$$(-x^3y^2+xza) : (x^2y^3)$$

For simplifying, I rewrote that as a fraction, and extracted an $x$:

$$\require{cancel}\frac{\cancel{𝚡}(-x^2y^2+za)}{\cancel{𝚡}(xy^3)}$$

But that's actually all I could come up with. The $... + za$ part got me confused.

Is there any further way to simplify this? There were some answer possibilities, but none matched what I got.

$$-\frac{x}{y} + x^{-1}zay^{-3}$$

$$-\frac{y}{x}^{-1} + \frac{xy^{-3}}{za}$$

$$\frac{-x+xza}{y}$$

$$\frac{za}{y}$$

• Could you write the possible answers? – mfl Oct 19 '17 at 7:45
• @mfl OK! Give me a second – Max Oct 19 '17 at 7:52

$$\frac{-x^2y^2+za}{xy^3}=\frac{-x^2y^2}{xy^3}+\frac{za}{xy^3}=\frac{-\cancel{xy^2}(x)}{\cancel{xy^2}(y)}+za(xy^3)^{-1}=-\frac{x}{y}+x^{-1}zay^{-3}$$ Hence, correct answer is Option A.
• You can show that $D$ isn't the answer since for $x=y=z=a=1$ the terms have different values.
• You can show that for $az \rightarrow \infty$ and $x,y$ constant your term goes to $\infty$, but the term from answer $B$ does not.
• You can see that for $za=1$ Answer $C$ has value $0$, $x$ doesn't matter. But in the original term $(-x^3y^2+x\cdot 1) : (x^2y^3)$ the value of $x$ does matter.
So $A$ is correct.