# Probability with cards without replacement

If theres 48 in a deck and 24 of them are red and 24 of them are black. Whats the probability that the next card is red, when 4 out of 12 cards drawn are red without replacement?

Does the success rate(4/12, 33%) influence what the next card drawn will be ? i.e. How would you go about this ?

If you've drawn 12 cards and four of them are red, then 8 are black. Therefore there are 36 cards left, 20 of which are red and 16 of which are black. So the probability of drawing a red card next is $\frac{20}{36} = \frac{5}{9}$.