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Ιf I have a $Z_n= (n^2+in)/(n^2 +1)$ am I right to assume that the real part is $n^2/(n^2 +1)$ and the imaginary part is $in/(n^2+1)$ it seems to simple to be that

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  • $\begingroup$ to ass${{{{}}}}$? $\endgroup$ – Lord Shark the Unknown Oct 14 '17 at 15:01
  • $\begingroup$ assume @LordSharktheUnknown $\endgroup$ – MCCCS Oct 14 '17 at 15:03
  • $\begingroup$ Sorry I meant assume $\endgroup$ – Rich Oct 14 '17 at 15:03
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    $\begingroup$ If $a$ and $b$ are real, then $b$ is the imaginary part of $a+ib$. $\endgroup$ – Lord Shark the Unknown Oct 14 '17 at 15:05
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    $\begingroup$ Only, if $n$ is real. If $n$ is complex, you have more work to do. $\endgroup$ – Laray Oct 14 '17 at 15:06
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Yes you can. $$Z_n = \frac{n^2 +in}{n^2+1}= \frac{n^2}{n^2 +1} + \frac{n}{n^2 +1} i $$ So the real part is $\frac{n^2}{n^2 +1}$ and the imaginary is $\frac{n}{n^2 +1}$ (without the $i$).

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