Find the number of all integer-sided isosceles obtuse-angled triangles with perimeter $2008$.
let sides be $x$, $x$, $y$ so $2x+y=2008$ , but by triangle inequality $y<2x$ also since it is obtuse-angled we can $y>x$.
these were my deductions, so how do I proceed further? any help is appreciated.
Thanks in advance!