Group action induces a homomorphism between Lie algebras

Let $\varphi:G\times M\rightarrow M$ be a Lie group $G$ (effective) action on a smooth manifold $M$.

Fix $g\in G$ and let $\varphi_g(x):=\varphi(g,x)$. Then $\varphi$ induces a smooth homomorphism $\lambda: G\rightarrow Aut(M);g\mapsto \varphi_g$.

Now, if $\frak g$ is the Lie algebra of $G$ and $\Gamma(M,TM)$ the algebra of smooth vector-fields on $M$. Then, is it true that $\lambda$ induces a homomorphism $\alpha:\mathfrak g \rightarrow \Gamma(M,TM)$? How $\alpha$ is defined? Is $\alpha$ injective? Can we say that the Lie algebra of $G$ is embedded in the Lie algebra of smooth vector-fields of $M$?

You get a linear map $\alpha\colon \mathfrak{ g} \to \Gamma(M,TM)$ as follows: For each $x\in M$ and $X\in \mathfrak g$, $$\alpha(X)_x = \left.\frac{d}{dt}\right|_{t=0} (\exp tX)\cdot x.$$ However, in the case of a left action, this is a Lie algebra anti-homomorphism, not a homomorphism. In the case of a right action, it's a homomorphism.