I have this formula: $$\frac{\sin x + 3\cos x}{2\cos x}$$ and I'm supposed to transform it so that I'm only left with one function (sin, cos, tan etc, just one of these). It should not be based on any complicated formulas/equations since it was originally a high school task, yet I have no idea how to tackle it. I always end up having at least one sin/cos and unable to get rid of it. I'm pretty sure I'm missing something simple but I'd appreciate any help. Thanks
2 Answers
$$ \frac{\sin x + 3 \cos x}{2 \cos x} = \frac{\sin x}{2 \cos x} + \frac{3 \cos x}{2 \cos x} = \frac{1}{2} \tan x + \frac{3}{2} $$