# Solve the following differential equation: $\frac {(ydx+xdy)}{(1-x^2y^2)}+xdx=0$

Is there any way I can get this into the form of a separable, Bernoulli, exact, or any other form of differential equation that is easy to solve?

Solve the following differential equation:

$$\frac{(ydx+xdy)}{(1-x^2y^2)}+xdx=0$$

can someone show me the procedure to simplify or convert this differential equation into a form that is easy to solve?

• Hint: $$ydx+xdy=d(xy)$$ – lab bhattacharjee Oct 5 '17 at 16:11
• @empty Just learn to solve problem yourself! – Nosrati Oct 5 '17 at 18:02

Let $xy=u$ and solve $$\int\dfrac{du}{1-u^2}=-\int xdx$$
$\dfrac{\mathrm d(xy}{1-(xy)^2}+x\mathrm dx=0 \\ \dfrac{1}{2} \ln \dfrac{1+xy}{1-xy}+\dfrac{x^2}{2} = c, \space some \space constant$