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I have this following equation: $ ae^{mx}+b e^{-mx}=c$

How do I solve for x here?? Assume that all a,b,c, and m are real numbers.

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    $\begingroup$ Is there supposed to be an $e$ after the $b$? $\endgroup$ – B. Goddard Sep 29 '17 at 4:49
  • $\begingroup$ Note that $r^y+r^{-y}=s$ is $(r^y)^2-sr^y+1=0$. $\endgroup$ – Gerry Myerson Sep 29 '17 at 5:38

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