# How to solve for x when it is in the power of e?

I have this following equation: $ae^{mx}+b e^{-mx}=c$

How do I solve for x here?? Assume that all a,b,c, and m are real numbers.

• Is there supposed to be an $e$ after the $b$? – B. Goddard Sep 29 '17 at 4:49
• Note that $r^y+r^{-y}=s$ is $(r^y)^2-sr^y+1=0$. – Gerry Myerson Sep 29 '17 at 5:38