The probability that A hits a target is 1/4 and the probability that B hits a target 1/3. They each fire once at the target.
If the target is hit by only one of them, what is the probability that A hits the target?
I know that this is an independent event. If I do P(A hitting) * P(B not hitting) then (1/4)(2/3) = 1/6 But when I look at the back of my book the answer is 2/5? My book is known to give wrong answers because it is quite old; therefore, I am left with self doubt. Can anyone tell me if I have the correct answer or if I am actually making a mistake?