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$$A=\begin{pmatrix}x&-3\\ y&3\end{pmatrix}$$

$A $ is the matrix above.

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    $\begingroup$ Hi, what have you tried? where do you get stuck? Also, can you tell us a bit about what do you know currently so that we can help you at the right level? $\endgroup$ Sep 24, 2017 at 6:50

1 Answer 1

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Calculate $A^2$

$$\begin{bmatrix}x&-3\\ y&3\end{bmatrix}\begin{bmatrix}x&-3\\ y&3\end{bmatrix}$$

$$=\begin{bmatrix}x^2-3y&-3x-9\\ xy+3y&-3y+9\end{bmatrix}$$

Then solve

$$x^2-3y=x$$

$$-3x-9=-3$$

$$xy+3y=y$$

$$-3y+9=3$$

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