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Hello stackexchange users! I am somewhat confused on $\sqrt{-1}$. I believe the answer should be no solution, or inconsistent, or at least something in that nature. Am I correct or am I most likely wrong? Any help or insight would be deeply appreciated


marked as duplicate by GAVD, Lord Shark the Unknown, Nosrati, Krish, Xam Sep 23 '17 at 2:54

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    $\begingroup$ Your answer is in the tags. $\endgroup$ – Parcly Taxel Sep 23 '17 at 1:53
  • $\begingroup$ Could you please clarify? $\endgroup$ – NerdOfCode Sep 23 '17 at 1:54
  • $\begingroup$ Just look up imaginary and complex numbers on Wikipedia. $\endgroup$ – Parcly Taxel Sep 23 '17 at 1:54
  • $\begingroup$ I asked this question on math.stackexchange.... I wasn't really looking for imaginary and complex numbers on Wikipedia. I simply wanted some clarification as you can see in my question. $\endgroup$ – NerdOfCode Sep 23 '17 at 1:56

if you consider all polynomials to have roots you can ask what is the root of x^2+1 well it turns out that this is only 0 when x =sqrt(-1) so imagine we have a value, i ,for the x that solves it. you can ask what set it's in but positive*positive=negative * negative = positive, so no positive or negative number works. to make sure all polynomials have roots you need to invent imaginary numbers.


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