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I am a bit puzzled. Trying to solve this system of equations:

\begin{align*} -x + 2y + z=0\\ x+2y+3z=0\\ \end{align*}

The solution should be \begin{align*} x=-z\\ y=-z\\ \end{align*}

I just don't get the same solution. Please advice.

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  • $\begingroup$ what solution did you obtain? to correct your mistake, I believe we need to know your working. $\endgroup$ – Siong Thye Goh Sep 19 '17 at 17:19
  • $\begingroup$ first, add the equations and see what you get. Then subtract the equations. $\endgroup$ – Vasya Sep 19 '17 at 17:19
  • $\begingroup$ According to my lecture notes I have now: \begin{align*} -x + 2y + z=0\\ y+z=0\\ \end{align*} But how to get to this point? I don't understand how it leads to this... $\endgroup$ – MiMaKo Sep 19 '17 at 17:26
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adding both equations we get $$y=-z$$ plugging this in the first equation we get $$-x-2z+z=0$$ tgherefore $$x=-z$$

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