Help would be much appreciated!
In a poker game ﬁve cards are dealt at random from an ordinary deck of 52 playing cards. Find the probability of: “Two pairs”, where the number of face value of the pairs are distinct, and the remaining card has a diﬀerent number or face value than either of the two pairs.
My solution: $((4/52)*(3/51)*(4/50)*(3/49)*(44/48))*13*nCr(???)$ Not sure if my approach is right.