I need to get $\Theta$ vector of weights for hyperplane in 3D that cuts off a single corner of a cube [1, 1, 1]. Cube's first corner is the origin. Or better to say I need to find a hyperplane that is tangent to a cube corner [1, 1, 1].

I am not strong in math to know how to do it. In fact, I never really worked on constructing hyperplanes. So not sure how to go about it.

EDIT: correct me if I am wrong, but I guess this question could also be stated as "constructing a hyperplane that is normal to a vector [1,1,1] and passes through point [1,1,1]"

Thank you


If a cube is centered at the origin, and t is some given real number, the hyperplane $x+y+z=t$ either misses the cube entirely, or separates a corner from the cube.


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.