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If there are 8 baskets of which five of them have chocolates. A kid is now allowed to pick any 5 baskets. What is the probability that the kid chooses the same five baskets which have chocolates in them?

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$\frac{1}{8\choose5}$ since there are 8 choose 5 ways of choosing five baskets and only one gives the desired outcome.

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  • $\begingroup$ I took a bigger route of P(a) and (b) and.... so on. This was much easier. Thanks ! $\endgroup$ – Chong Su Sep 10 '17 at 23:30

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