Probabilities that are "missing" in the normal distribution table

Question

I have some difficulties using Normal tables, this is the table that I'm using.

I have the following example:

$\begin{array}{lcl}P(Z > 1.377) & = & Q(1.377) \\ & = & 0.0842 \end{array}\\$

How can I find the value $Q(1.377)$ from that table?
Looking at that table I can see only $Q(1.37) = 0.0853$

I have tried, but, without success to considered this:
$Q(1.38) + \int_{1.377}^{1.38} \frac{1}{\sqrt{2 \pi}}e^{-\frac{1}{2}z^2} dx \quad \mbox{ with} \quad -\infty < z < \infty$

or also:

$Q(1.37) - \int_{1.377}^{1.37} \frac{1}{\sqrt{2 \pi}}e^{-\frac{1}{2}z^2} dx \quad \mbox{ with} \quad -\infty < z < \infty$

please, can you help me? Thanks!

Answer 1

You can approximate it as $Q(1.38)+0.3(Q(1.37)-Q(1.38))$, where the $3$ comes because you went 30% of the way from 1.38 to 1.37. This linear interpolation technique is usually how students are taught to do it in elementary statistics.