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Let a belong to the set of (Rationals - Integers)

How would you prove the following:

a squared belongs to the set of (Rationals - Integers)

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    $\begingroup$ The body of the question doesn't match the title. Which one are you asking? In case it matters, remember that $\,i^2=-1\,$, and $\big(\sqrt{2}\big)^2=2$. $\endgroup$
    – dxiv
    Aug 30, 2017 at 22:42
  • $\begingroup$ Sorry I meant set of Complex minus set of Integers $\endgroup$
    – user448724
    Aug 30, 2017 at 22:43
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    $\begingroup$ $i^2=-1$ your statement is false. $\endgroup$ Aug 30, 2017 at 22:46
  • $\begingroup$ Ah yes of course. I'm going to update the question to be irrational set minus integer. $\endgroup$
    – user448724
    Aug 30, 2017 at 22:49
  • $\begingroup$ If the dupes don't answer your question then please clarify why and we can reopen the question. $\endgroup$ Aug 30, 2017 at 23:01

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