0
$\begingroup$

Let a belong to the set of (Rationals - Integers)

How would you prove the following:

a squared belongs to the set of (Rationals - Integers)

$\endgroup$

marked as duplicate by Matthew Conroy, dxiv, CIJ, Bill Dubuque number-theory Aug 30 '17 at 22:59

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

  • 2
    $\begingroup$ The body of the question doesn't match the title. Which one are you asking? In case it matters, remember that $\,i^2=-1\,$, and $\big(\sqrt{2}\big)^2=2$. $\endgroup$ – dxiv Aug 30 '17 at 22:42
  • $\begingroup$ Sorry I meant set of Complex minus set of Integers $\endgroup$ – user448724 Aug 30 '17 at 22:43
  • 1
    $\begingroup$ $i^2=-1$ your statement is false. $\endgroup$ – hamam_Abdallah Aug 30 '17 at 22:46
  • $\begingroup$ Ah yes of course. I'm going to update the question to be irrational set minus integer. $\endgroup$ – user448724 Aug 30 '17 at 22:49
  • $\begingroup$ If the dupes don't answer your question then please clarify why and we can reopen the question. $\endgroup$ – Bill Dubuque Aug 30 '17 at 23:01