Here is the question:
To find the volume of a right circular cone with base radius $r$ and height $h$, the cone is divided into $n$ frustums of equal heights. The volume of each frustum is approximated as if it were a circular cylinder, having the larger of the tow plane surfaces as the base of the cylinder. Show that the approximate volume of the cone is $V_n =(1/6)(2πrh)(1+1/n)(2+1/n)$. Hence, find the actual volume of the cone.
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I am stuck for a few hours and i really need ur help, thanks!! :)