# Finding the stability of origin in a Lorentz system symbolically -no integer value solution

Finding the stability of the origin fixed point in a Lorentz system.

The Lorentz equation:

$\dot{x}=\sigma\left ( y-x \right )$

$\dot{y}=rx-y-xz$

$\dot{z}=-bz+xy$

The Jacobian evaluated at the fixed point $\left ( 0,0,0 \right )$:

$J\mid _{\left ( 0,0,0 \right )}=\begin{bmatrix} -\sigma &\sigma &0 \\ r &-1 &0 \\ 0&0 &-b \end{bmatrix}$

We seek $det\left ( J \mid _{\left ( 0,0,0 \right )}-\lambda I \right )=0$

We compute the $3\times 3$ matrix:

This gives: to save you helpful souls from working it out

Setting the above result to 0, and rearranging the term to $\lambda^{3}$, $\lambda^{2}$, $\lambda$ and the constants, there is no integer valued solutions to be found.

How should I get around this conundrum?

Any explanation to expand my understanding is greatly appreciated.

• This post is related. Sep 4 '17 at 12:59

• Yeah, but take into account that usually you don't need to solve quadratic equations to say something about its roots. For example, if you have equation $\lambda^2 +a \lambda + b = 0$ and $b < 0$ the roots are always real and have different signs. If $b > 0$ the roots always have the same real part the sign of which depends on $a$. It's easier to analyze the roots this way than by analyzing roots from discriminant formula. Jul 29 '17 at 6:08