# A four sided fair dice is rolled 10 times. What is the probability of two sides being absent and two sides being present?

When solving this question

A four sided fair dice is rolled 10 times. What is the probability of two sides being absent and two sides being present?

I get the result $$\frac{{4 \choose 2} \cdot 2^{10}}{4^{10}}$$ yet the official answer is $$\frac{{4 \choose 2}(2^{10}-2)}{4^{10}}$$ Anyone who can explain where this $-2$ comes from?