# Help with this formula I'm trying to make

.75 - size * (n - 3) / steps


Assuming b = 3:

When assigning 3 to n, the formula will result in 0.75, n = 4 will result in 0.5 and n = 5 will result in 0.25. Which is exactly what I wanted.

Now, I want to add 2 parameters to this formula. steps and size.

If steps = 2, and size = 0.25 (b is still 3), n = 3 would result in 0.75 and n = 5 would result in 0.5, and n = 7 would result in 0.25. I hope you're following!

What steps should I make in order to successfully integrate these 2 parameters into my formula? Would that be possible or should I make a new formula?

I'm not a mathematician, at all.

• What do you mean by 'results in' - are you trying to solve w.r.t. $a$? Are the two lines one equation? – DominikS Jul 25 '17 at 15:47
• I'm finding it hard to follow what you're after. Perhaps if you added some context it'd be easier to understand? Or make a table of $a,b,n,\text{steps},\text{size}$ with some example values so we can see the pattern you're after easier – Shuri2060 Jul 25 '17 at 15:48
• @DominikS the result of the formula – K. Moe Jul 25 '17 at 15:49
• " I hope you're following!" I can assure you nobody is. You haven't described in any sense how steps modifies anything. You merely state that if steps is 2 then the value for n=3 will be the same as it was when steps wasn't specified (but presumably set to some unknown value but that n=5 will have a different result whereas n =4 with no steps and n= with two steps are given with no value to compare. Meanwhile size is not integrated or explained for any reason. Why don't you actually try to tell us what the formula is supposed to DO? – fleablood Jul 25 '17 at 16:12
• You should read your own post after forgetting all you know about the problem. You will realize that it is of the kind: "if $a=2$ and we don't use $\xi$, what is $v'$ ?" – Yves Daoust Jul 25 '17 at 16:51

$$f(n,b,\text {steps},\text{size}) = \begin{cases} 0.75,&& n=3,\text {steps}=0.25, \text{size}=0.5, b=3 \\\ 0.5,&& n=5,\text {steps}=0.25, \text{size}=0.5, b=3 \\\ 0.25,&& n=7,\text {steps}=0.25, \text{size}=0.5,b=3 \\\ 0.75\times (2 - (n / b)), &&\text{otherwise} \\ \end{cases}$$