Trying to work out the probability of rolling doubles on two six sided dice (2d6) vs one four sided die (d4) and one six sided die. Maths isn't my strong suit. Little help?
'Kay, so the odds of rolling a double on 2d6 is nice and simple. There are 6 possible ways of rolling doubles on 2d6 out of a possible 36 combinations, so (1/(6*6))*6 = 0.167, or a 17ish percent chance of rolling a double.
There are 24 combinations of a d6 and a d4, and 4 ways of rolling doubles. So (1/(6*4))*4 = ... also 0.167. Exactly the same chance of rolling a double.
That doesn't seem right to me? I'd assumed that you'd be less likely to roll doubles on a d4 and a d6. So which is wrong, my maths or my intuition?