I've been trying to solve this exercise for a few hours, I can't seem to get the right answer. Can someone share the intuition or twist behind this problem? I'll perhaps try to take it from there.
An urn contains 10 blue balls , 5 yellow balls and 5 red balls. Six balls are drawn from the urn and discarded, their color unnoticed. A second sample of 8 balls is then drawn without replacement. What is the probability that the latter contains 4 blue balls, 1 yellow ball and 3 red balls.