I found the $x$-intercept by setting $y= 0$ so here goes:

$$0=-2x+1\implies -1=-2x\implies x=\frac{1}{2}$$

The sketch I saw of this graph though ,has a different $x$-intercept.

How could I work this out properly ?

  • 4
    $\begingroup$ Your calculation above is correct. The sketch must either be incorrect or you looked at the $x$-intercept wrong. The $x$-intercept is indeed $\frac{1}{2}$ $\endgroup$
    – Dave
    Jun 20 '17 at 15:48
  • $\begingroup$ Is it possible for you to show us that sketch? $\endgroup$ Jun 20 '17 at 15:51
  • $\begingroup$ Sorry I'm not very good with computers. $\endgroup$ Jun 20 '17 at 15:51
  • $\begingroup$ Just copy y=−2x+1 and paste it on the Google :-) $\endgroup$ Jun 20 '17 at 15:52
  • $\begingroup$ What is the $x$-intercept you found from your sketch? $\endgroup$ Jun 20 '17 at 15:57

You've found the correct $x$-intercept, $(\frac{1}{2},0)$. Perhaps you've made a typo in your graphing, or the axes could be scaled in a strange way that make it look wrong. Here is the graph of the line from WolframAlpha, with the x-intercept pointed out:



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