# $2$ chosen squares from a chess board have neither any side nor any corner in common

$2$ squares $(1\times 1)$ are chosen at random from a chess board,

Then find the number of ways in which $2$ chosen square have neither any side nor any corner in common.

$\bf{Attempt}$ Number of ways of choosing squares is $\displaystyle \binom{64}{2}$

Number of ways in which exactly one side is common is $\displaystyle 2(7\times 7) = 98$

Now how can I calculate for a corner in common?

Thanks.

• Two squares are chosen at random out of what? From the use of $64$ maybe you mean only $1 \times 1$ squares out of an $8 \times 8$ grid. Wouldn't it be better to explain that? – Ross Millikan Jun 20 '17 at 2:16
• yes Ross Millikan – DXT Jun 20 '17 at 2:18